3x+2=x^2+4x+3

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Solution for 3x+2=x^2+4x+3 equation:



3x+2=x^2+4x+3
We move all terms to the left:
3x+2-(x^2+4x+3)=0
We get rid of parentheses
-x^2+3x-4x-3+2=0
We add all the numbers together, and all the variables
-1x^2-1x-1=0
a = -1; b = -1; c = -1;
Δ = b2-4ac
Δ = -12-4·(-1)·(-1)
Δ = -3
Delta is less than zero, so there is no solution for the equation

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